Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 21:39Z
10y² + 2y + 6 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
460K
∫₀^∞ e^(-t²) dt = √π / 2
\lim_{β\to 0} \frac{\sin β}{β} = 1
411K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
22K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\lim_{t\to 0} \frac{\sin t}{t} = 1
459K
\lim_{r\to 0} \frac{\sin r}{r} = 1
406K