Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 12:40Z

∑_{k=1}^{n} k = n(n+1)/2

12θ² + 2θ + 6 = 0

460K

∂β/∂β = 6β

438K

4y² + 7y + 7 = 0

∇²z = 0

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

∇²t = 0

e^{i\pi} + 1 = 0

448K

4γ² + 1γ + 7 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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iħ ∂ψ/∂t = Ĥψ

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∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

80K

det| 7 4 ; 4 8 | = 40

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∫₀^∞ e^(-x²) dx = √π / 2

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