Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:14Z

11t² + 8t + 0 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

CH₄ + 2O₂ → CO₂ + 2H₂O

438K

∂ω/∂β = 7ω

det| 7 4 ; 4 8 | = 40

186K

10ω² + 7ω + 4 = 0

411K

det| 3 3 ; 7 4 | = -9

\lim_{r\to 0} \frac{\sin r}{r} = 1

448K

det| 3 7 ; 2 4 | = -2

22K

PV = nRT

∇²ω = 0

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

∑_{k=1}^{n} k = n(n+1)/2

181K