Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:15Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

∇ × E = −∂B/∂t

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∫₀^∞ e^(-x²) dx = √π / 2

det| 4 2 ; 6 5 | = 8

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∇²θ = 0

411K

4φ² + 6φ + 2 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

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∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

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∂y/∂γ = 8y

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d/dt [t^3] = 3t^2

181K

\oint_C \vec{F}\cdot d\vec{r} = 0

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11φ² + 4φ + 0 = 0

359K

8ψ² + 7ψ + 0 = 0

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