Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:50Z

det| 5 4 ; 6 6 | = 6

∑_{k=1}^{n} k = n(n+1)/2

460K

d/dt [t^3] = 3t^2

438K

∇²φ = 0

∇²β = 0

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

det| 12 5 ; 4 13 | = 136

∑_{k=1}^{n} k = n(n+1)/2

448K

\frac{4}{6} \sum_{i=1}^{n} i^{2}

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∑_{k=1}^{n} k = n(n+1)/2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

406K

CaCO₃ → CaO + CO₂

det| 9 4 ; 1 10 | = 86

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

det| 5 2 ; 3 6 | = 24

359K

∇ × E = −∂B/∂t

455K