Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:44Z

d/dy [y^8] = 8y^7

∑_{k=1}^{n} k = n(n+1)/2

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8ψ² + 7ψ + 0 = 0

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\lim_{x\to 0} \frac{\sin x}{x} = 1

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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iħ ∂ψ/∂t = Ĥψ

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d/dn [n^3] = 3n^2

∂α/∂ω = 3α

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iħ ∂ψ/∂t = Ĥψ

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6t² + 4t + 0 = 0

N₂ + 3H₂ ⇌ 2NH₃

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∂ψ/∂β = 3ψ

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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