Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:43Z

10y² + 2y + 6 = 0

∇ × E = −∂B/∂t

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\oint_C \vec{F}\cdot d\vec{r} = 0

438K

∫₀^∞ e^(-t²) dt = √π / 2

e^{i\pi} + 1 = 0

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det| 12 2 ; 2 13 | = 152

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e^{i\pi} + 1 = 0

F = G m₁m₂ / r²

448K

2n² + 4n + 0 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 7 4 ; 4 8 | = 40

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iħ ∂ψ/∂t = Ĥψ

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PV = nRT

181K

∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-t²) dt = √π / 2

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