Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:37Z

11n² + 5n + 4 = 0

∇ × E = −∂B/∂t

460K

2H₂ + O₂ → 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

186K

ΔS ≥ 0

411K

4φ² + 6φ + 2 = 0

CaCO₃ → CaO + CO₂

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

F = G m₁m₂ / r²

459K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

406K

det| 7 4 ; 4 8 | = 40

181K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

80K

F = G m₁m₂ / r²

359K

9ψ² + 7ψ + 3 = 0

455K