Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 18:30Z

e^{i\pi} + 1 = 0

N₂ + 3H₂ ⇌ 2NH₃

451K

PV = nRT

264K

λ = h/p

det| 3 1 ; 7 4 | = 5

297K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

252K

det| 6 7 ; 7 7 | = -7

7r² + 8r + 5 = 0

48K

d/dt [t^3] = 3t^2

411K

det| 9 4 ; 1 10 | = 86

377K

∫₀^∞ e^(-t²) dt = √π / 2

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∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

420K

∂γ/∂z = 6γ

109K