Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 17:09Z

det| 11 2 ; 2 12 | = 128

∇ × E = −∂B/∂t

460K

∫₀^∞ e^(-t²) dt = √π / 2

438K

CaCO₃ → CaO + CO₂

7r² + 8r + 5 = 0

186K

det| 7 4 ; 4 8 | = 40

411K

3θ² + 7θ + 1 = 0

F = ma

448K

F = G m₁m₂ / r²

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 4 7 ; 2 5 | = 6

459K

\lim_{t\to 0} \frac{\sin t}{t} = 1

406K

2H₂ + O₂ → 2H₂O

∇ × E = −∂B/∂t

∫₀^∞ e^(-z²) dz = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O