Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:20Z

3γ² + 8γ + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

d/dt [t^3] = 3t^2

438K

PV = nRT

\lim_{t\to 0} \frac{\sin t}{t} = 1

186K

det| 3 6 ; 0 4 | = 12

411K

det| 1 9 ; 5 2 | = -43

8ψ² + 7ψ + 0 = 0

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

ω = 2πf

∇ × E = −∂B/∂t

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

∂n/∂ψ = 6n