Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:57Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

iħ ∂ψ/∂t = Ĥψ

438K

∫₀^∞ e^(-x²) dx = √π / 2

d/dx [x^3] = 3x^2

186K

∫₀^∞ e^(-θ²) dθ = √π / 2

411K

4φ² + 6φ + 2 = 0

e^{i\pi} + 1 = 0

448K

F = G m₁m₂ / r²

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\oint_C \vec{F}\cdot d\vec{r} = 0

459K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

406K

∇²ω = 0

d/dx [x^9] = 9x^8

181K

e^{i\pi} + 1 = 0

80K

d/dr [r^2] = 2r^1

det| 9 4 ; 1 10 | = 86

359K

4γ² + 1γ + 7 = 0

455K