Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 22:01Z
3n² + 7n + 7 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
438K
∫₀^∞ e^(-ω²) dω = √π / 2
\frac{10}{6} \sum_{i=1}^{n} i^{2}
d/dr [r^12] = 12r^11
d/dφ [φ^5] = 5φ^4
∑_{k=1}^{n} k = n(n+1)/2
181K
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-θ²) dθ = √π / 2
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 4 8 ; 3 5 | = -4