Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:48Z

3γ² + 8γ + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

PV = nRT

det| 4 7 ; 2 5 | = 6

186K

det| 7 4 ; 4 8 | = 40

411K

det| 1 9 ; 5 2 | = -43

∂ψ/∂β = 3ψ

448K

det| 2 3 ; 5 3 | = -9

22K

ω = 2πf

∂y/∂γ = 8y

459K

5z² + 8z + 3 = 0

406K

N₂ + 3H₂ ⇌ 2NH₃

181K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

80K

∑_{k=1}^{n} k = n(n+1)/2

359K