Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:02Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∫₀^∞ e^(-θ²) dθ = √π / 2

438K

∫₀^∞ e^(-x²) dx = √π / 2

iħ ∂ψ/∂t = Ĥψ

186K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

411K

4φ² + 6φ + 2 = 0

det| 5 2 ; 3 6 | = 24

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

11t² + 9t + 5 = 0

181K

∫₀^∞ e^(-t²) dt = √π / 2

80K

8ψ² + 7ψ + 0 = 0

359K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

455K