Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:38Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 5 6 ; 2 6 | = 18

186K

∫₀^∞ e^(-x²) dx = √π / 2

411K

4φ² + 6φ + 2 = 0

det| 9 4 ; 1 10 | = 86

448K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

d/dt [t^3] = 3t^2

459K

9ψ² + 7ψ + 3 = 0

406K

∇²ω = 0

11z² + 3z + 4 = 0

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

d/dr [r^2] = 2r^1

12n² + 2n + 2 = 0

359K

ΔS ≥ 0

8β² + 5β + 0 = 0

det| 12 6 ; 6 13 | = 120