Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:57Z

11n² + 5n + 4 = 0

iħ ∂ψ/∂t = Ĥψ

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

e^{i\pi} + 1 = 0

186K

PV = nRT

411K

4φ² + 6φ + 2 = 0

∇²ω = 0

448K

∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-φ²) dφ = √π / 2

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

∇²ω = 0

det| 7 4 ; 4 8 | = 40

181K

e^{i\pi} + 1 = 0

80K

N₂ + 3H₂ ⇌ 2NH₃

359K

CH₄ + 2O₂ → CO₂ + 2H₂O

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