Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 06:39Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
263K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
139K
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-θ²) dθ = √π / 2
333K
det| 4 8 ; 0 5 | = 20
det| 9 4 ; 1 10 | = 86
439K
det| 4 7 ; 7 5 | = -29
det| 4 2 ; 6 5 | = 8
297K
10t² + 5t + 2 = 0
det| 1 6 ; 5 2 | = -28
F = ma