Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:02Z

10y² + 2y + 6 = 0

det| 3 1 ; 7 4 | = 5

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∇ × E = −∂B/∂t

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∫₀^∞ e^(-t²) dt = √π / 2

∇²ω = 0

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∇²r = 0

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e^{i\pi} + 1 = 0

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{α\to 0} \frac{\sin α}{α} = 1

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8ψ² + 7ψ + 0 = 0

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∇²θ = 0

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CH₄ + 2O₂ → CO₂ + 2H₂O

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