Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:23Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

PV = nRT

438K

∫₀^∞ e^(-x²) dx = √π / 2

PV = nRT

186K

det| 11 4 ; 5 12 | = 112

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4φ² + 6φ + 2 = 0

det| 1 4 ; 3 2 | = -10

448K

iħ ∂ψ/∂t = Ĥψ

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det| 9 4 ; 1 10 | = 86

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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F = G m₁m₂ / r²

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11z² + 3z + 4 = 0

80K

e^{i\pi} + 1 = 0

359K