Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z

∇²n = 0

∑_{k=1}^{n} k = n(n+1)/2

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2H₂ + O₂ → 2H₂O

263K

9r² + 4r + 1 = 0

6n² + 7n + 6 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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11γ² + 3γ + 6 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

439K

∑_{k=1}^{n} k = n(n+1)/2

413K

2n² + 4n + 0 = 0

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det| 7 4 ; 4 8 | = 40

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det| 8 9 ; 4 9 | = 36

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