Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:37Z

10y² + 2y + 6 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-t²) dt = √π / 2

λ = h/p

186K

d/dt [t^3] = 3t^2

411K

e^{i\pi} + 1 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

det| 2 6 ; 0 3 | = 6

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∇²ω = 0

459K

d/dφ [φ^1] = 1φ^0

406K

∇ × E = −∂B/∂t

181K

E = mc²

80K

8ψ² + 7ψ + 0 = 0

359K