Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 04:58Z

e^{i\pi} + 1 = 0

det| 4 8 ; 3 5 | = -4

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∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∫₀^∞ e^(-ω²) dω = √π / 2

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F = G m₁m₂ / r²

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\frac{1}{1} \sum_{i=1}^{n} i^{2}

8ψ² + 7ψ + 0 = 0

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iħ ∂ψ/∂t = Ĥψ

411K

λ = h/p

11φ² + 4φ + 0 = 0

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\frac{4}{9} \sum_{i=1}^{n} i^{2}

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∑_{k=1}^{n} k = n(n+1)/2

∂α/∂ω = 3α

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∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

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