Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:14Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

10t² + 9t + 5 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

det| 11 9 ; 0 12 | = 132

411K

4φ² + 6φ + 2 = 0

8ψ² + 7ψ + 0 = 0

448K

7r² + 8r + 5 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

d/dt [t^3] = 3t^2

459K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

406K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

181K

\frac{12}{6} \sum_{i=1}^{n} i^{2}

80K

∇ × E = −∂B/∂t

359K