Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:51Z
∇²n = 0
∫₀^∞ e^(-t²) dt = √π / 2
273K
∑_{k=1}^{n} k = n(n+1)/2
263K
9r² + 4r + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 7 4 ; 4 8 | = 40
333K
det| 3 1 ; 7 4 | = 5
297K
∑_{k=1}^{n} k = n(n+1)/2
128K