Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 12:36Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
438K
4y² + 7y + 7 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
186K
∇²t = 0
det| 11 5 ; 0 12 | = 132
448K
6β² + 2β + 2 = 0
2φ² + 2φ + 5 = 0
det| 7 9 ; 1 8 | = 47
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∫₀^∞ e^(-ψ²) dψ = √π / 2
80K
det| 9 4 ; 1 10 | = 86
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