Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:27Z

d/dy [y^8] = 8y^7

∇ × E = −∂B/∂t

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CH₄ + 2O₂ → CO₂ + 2H₂O

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\lim_{x\to 0} \frac{\sin x}{x} = 1

5φ² + 1φ + 1 = 0

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d/dt [t^3] = 3t^2

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d/dn [n^3] = 3n^2

∑_{k=1}^{n} k = n(n+1)/2

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\frac{4}{9} \sum_{i=1}^{n} i^{2}

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6t² + 4t + 0 = 0

∂y/∂γ = 8y

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CH₄ + 2O₂ → CO₂ + 2H₂O

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N₂ + 3H₂ ⇌ 2NH₃

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det| 9 4 ; 1 10 | = 86

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