Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:36Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

det| 3 7 ; 2 4 | = -2

438K

∫₀^∞ e^(-x²) dx = √π / 2

8ψ² + 7ψ + 0 = 0

186K

iħ ∂ψ/∂t = Ĥψ

411K

4φ² + 6φ + 2 = 0

\oint_C \vec{F}\cdot d\vec{r} = 0

448K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

459K

\frac{12}{6} \sum_{i=1}^{n} i^{2}

406K

∇²ω = 0

d/dα [α^3] = 3α^2

d/dr [r^2] = 2r^1

ΔS ≥ 0