Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:36Z

N₂ + 3H₂ ⇌ 2NH₃

N₂ + 3H₂ ⇌ 2NH₃

246K

∑_{k=1}^{n} k = n(n+1)/2

118K

9ψ² + 4ψ + 2 = 0

6t² + 6t + 4 = 0

43K

iħ ∂ψ/∂t = Ĥψ

261K

d/dβ [β^6] = 6β^5

8ψ² + 7ψ + 0 = 0

424K

N₂ + 3H₂ ⇌ 2NH₃

76K

det| 6 1 ; 4 7 | = 38

Fe₂O₃ + 3CO → 2Fe + 3CO₂

41K

∑_{k=1}^{n} k = n(n+1)/2

298K

\frac{6}{5} \sum_{i=1}^{n} i^{2}

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

447K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

297K

11y² + 2y + 6 = 0

det| 10 3 ; 1 11 | = 107

2H₂ + O₂ → 2H₂O

Fe₂O₃ + 3CO → 2Fe + 3CO₂