Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:38Z

10y² + 2y + 6 = 0

∫₀^∞ e^(-t²) dt = √π / 2

460K

λ = h/p

438K

∫₀^∞ e^(-t²) dt = √π / 2

e^{i\pi} + 1 = 0

186K

\lim_{β\to 0} \frac{\sin β}{β} = 1

411K

e^{i\pi} + 1 = 0

∇ × E = −∂B/∂t

448K

8ψ² + 7ψ + 0 = 0

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

∇²r = 0

406K

λ = h/p

d/dt [t^3] = 3t^2

181K

ω = 2πf

80K

d/dγ [γ^3] = 3γ^2

CH₄ + 2O₂ → CO₂ + 2H₂O