Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:32Z

10γ² + 4γ + 3 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

det| 9 5 ; 1 10 | = 85

438K

d/dβ [β^11] = 11β^10

∑_{k=1}^{n} k = n(n+1)/2

186K

d/dt [t^3] = 3t^2

411K

3x² + 4x + 6 = 0

∂ψ/∂β = 3ψ

448K

F = G m₁m₂ / r²

22K

CaCO₃ → CaO + CO₂

∇ × E = −∂B/∂t

459K

8ψ² + 7ψ + 0 = 0

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

\lim_{r\to 0} \frac{\sin r}{r} = 1

181K

∫₀^∞ e^(-α²) dα = √π / 2

80K

∑_{k=1}^{n} k = n(n+1)/2

Fe₂O₃ + 3CO → 2Fe + 3CO₂

359K

F = ma

3n² + 3n + 5 = 0

5z² + 1z + 0 = 0