Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:53Z

d/dy [y^8] = 8y^7

iħ ∂ψ/∂t = Ĥψ

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∫₀^∞ e^(-t²) dt = √π / 2

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\lim_{x\to 0} \frac{\sin x}{x} = 1

6x² + 6x + 1 = 0

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iħ ∂ψ/∂t = Ĥψ

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d/dn [n^3] = 3n^2

∫₀^∞ e^(-θ²) dθ = √π / 2

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∑_{k=1}^{n} k = n(n+1)/2

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6t² + 4t + 0 = 0

∂x/∂ψ = 6x

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\oint_C \vec{F}\cdot d\vec{r} = 0

det| 9 4 ; 1 10 | = 86

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F = G m₁m₂ / r²

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e^{i\pi} + 1 = 0

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