Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:23Z

11n² + 5n + 4 = 0

N₂ + 3H₂ ⇌ 2NH₃

460K

5z² + 8z + 3 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇²ω = 0

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

4φ² + 6φ + 2 = 0

8θ² + 8θ + 6 = 0

448K

8ψ² + 7ψ + 0 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

iħ ∂ψ/∂t = Ĥψ

459K

12y² + 5y + 7 = 0

406K

∇²ω = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

359K

det| 10 2 ; 3 11 | = 104

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