Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 05:27Z

λ = h/p

8ψ² + 7ψ + 0 = 0

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det| 10 2 ; 3 11 | = 104

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det| 3 9 ; 5 4 | = -33

d/dt [t^3] = 3t^2

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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iħ ∂ψ/∂t = Ĥψ

iħ ∂ψ/∂t = Ĥψ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 8 7 ; 0 9 | = 72

∇²ω = 0

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∇ × E = −∂B/∂t

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∫₀^∞ e^(-x²) dx = √π / 2

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