Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:36Z

3γ² + 8γ + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

PV = nRT

∑_{k=1}^{n} k = n(n+1)/2

186K

d/dt [t^3] = 3t^2

411K

det| 1 9 ; 5 2 | = -43

PV = nRT

448K

det| 9 4 ; 1 10 | = 86

22K

ω = 2πf

det| 11 5 ; 0 12 | = 132

459K

PV = nRT

406K

∑_{k=1}^{n} k = n(n+1)/2

181K

det| 9 8 ; 3 10 | = 66

80K