Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 01:07Z

12γ² + 2γ + 2 = 0

4t² + 3t + 3 = 0

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∫₀^∞ e^(-z²) dz = √π / 2

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∑_{k=1}^{n} k = n(n+1)/2

d/dt [t^3] = 3t^2

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∑_{k=1}^{n} k = n(n+1)/2

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5φ² + 3φ + 0 = 0

det| 9 8 ; 3 10 | = 66

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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ΔS ≥ 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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det| 9 4 ; 1 10 | = 86

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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10ψ² + 5ψ + 0 = 0

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det| 3 7 ; 2 4 | = -2

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∑_{k=1}^{n} k = n(n+1)/2

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