Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:28Z

∇²n = 0

∑_{k=1}^{n} k = n(n+1)/2

273K

N₂ + 3H₂ ⇌ 2NH₃

263K

9r² + 4r + 1 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

139K

N₂ + 3H₂ ⇌ 2NH₃

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∇²r = 0

333K

det| 5 6 ; 2 6 | = 18

160K

11γ² + 3γ + 6 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

439K

2H₂ + O₂ → 2H₂O

413K

det| 7 4 ; 4 8 | = 40

297K

4t² + 3t + 3 = 0

128K

e^{i\pi} + 1 = 0

404K

∑_{k=1}^{n} k = n(n+1)/2

58K