Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 19:21Z

\frac{11}{4} \sum_{i=1}^{n} i^{2}

d/dt [t^3] = 3t^2

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∑_{k=1}^{n} k = n(n+1)/2

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d/dx [x^3] = 3x^2

N₂ + 3H₂ ⇌ 2NH₃

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det| 9 4 ; 1 10 | = 86

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\frac{12}{8} \sum_{i=1}^{n} i^{2}

iħ ∂ψ/∂t = Ĥψ

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det| 10 7 ; 3 11 | = 89

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∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-α²) dα = √π / 2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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