Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:49Z

10y² + 2y + 6 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-t²) dt = √π / 2

11t² + 9t + 7 = 0

186K

CH₄ + 2O₂ → CO₂ + 2H₂O

411K

e^{i\pi} + 1 = 0

N₂ + 3H₂ ⇌ 2NH₃

448K

det| 7 4 ; 4 8 | = 40

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\binom{n}{k} = \frac{n!}{k!(n-k)!}

459K

∇²t = 0

406K

λ = h/p

∑_{k=1}^{n} k = n(n+1)/2

181K