Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 21:41Z
10y² + 2y + 6 = 0
∫₀^∞ e^(-t²) dt = √π / 2
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
448K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 11 5 ; 0 12 | = 132
459K
det| 7 2 ; 7 8 | = 42
406K
λ = h/p