Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:23Z

11n² + 5n + 4 = 0

iħ ∂ψ/∂t = Ĥψ

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-x²) dx = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

det| 10 2 ; 3 11 | = 104

411K

4φ² + 6φ + 2 = 0

∇²γ = 0

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

∇²ω = 0

8ψ² + 7ψ + 0 = 0

181K

d/dα [α^3] = 3α^2

d/dr [r^2] = 2r^1

ΔS ≥ 0