Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:50Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

∇ × E = −∂B/∂t

186K

8ψ² + 7ψ + 0 = 0

411K

4φ² + 6φ + 2 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

448K

6n² + 7n + 6 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

e^{i\pi} + 1 = 0

459K

CaCO₃ → CaO + CO₂

406K

E = mc²

181K

d/dt [t^3] = 3t^2

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