Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 03:05Z

∇²x = 0

∑_{k=1}^{n} k = n(n+1)/2

451K

d/dt [t^3] = 3t^2

264K

det| 3 9 ; 1 4 | = 3

e^{i\pi} + 1 = 0

297K

∇²ω = 0

252K

CaCO₃ → CaO + CO₂

det| 11 4 ; 5 12 | = 112

48K

∫₀^∞ e^(-θ²) dθ = √π / 2

411K

det| 8 9 ; 4 9 | = 36

∑_{k=1}^{n} k = n(n+1)/2

377K

det| 9 4 ; 1 10 | = 86

299K

det| 7 6 ; 6 8 | = 20

det| 8 4 ; 3 9 | = 60