Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 16:56Z
10γ² + 4γ + 3 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
438K
d/dβ [β^11] = 11β^10
∑_{k=1}^{n} k = n(n+1)/2
186K
3x² + 4x + 6 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
448K
det| 7 4 ; 4 8 | = 40
22K
det| 10 7 ; 3 11 | = 89
459K
det| 11 5 ; 0 12 | = 132
406K
∫₀^∞ e^(-t²) dt = √π / 2
80K