Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:39Z

10γ² + 4γ + 3 = 0

det| 9 5 ; 1 10 | = 85

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

d/dβ [β^11] = 11β^10

\lim_{α\to 0} \frac{\sin α}{α} = 1

186K

iħ ∂ψ/∂t = Ĥψ

411K

3x² + 4x + 6 = 0

\frac{4}{6} \sum_{i=1}^{n} i^{2}

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

CaCO₃ → CaO + CO₂

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

N₂ + 3H₂ ⇌ 2NH₃

181K

∫₀^∞ e^(-t²) dt = √π / 2

80K

8ψ² + 7ψ + 0 = 0

359K