Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:40Z

3γ² + 8γ + 4 = 0

1n² + 7n + 3 = 0

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∇ × E = −∂B/∂t

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PV = nRT

det| 4 8 ; 3 5 | = -4

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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det| 1 9 ; 5 2 | = -43

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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ω = 2πf

\lim_{t\to 0} \frac{\sin t}{t} = 1

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8ψ² + 7ψ + 0 = 0

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∫₀^∞ e^(-α²) dα = √π / 2

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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