Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 12:36Z

∑_{k=1}^{n} k = n(n+1)/2

d/dt [t^3] = 3t^2

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e^{i\pi} + 1 = 0

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4y² + 7y + 7 = 0

det| 9 4 ; 1 10 | = 86

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∂β/∂β = 6β

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∇²t = 0

det| 1 4 ; 3 2 | = -10

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∑_{k=1}^{n} k = n(n+1)/2

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6β² + 2β + 2 = 0

\frac{4}{9} \sum_{i=1}^{n} i^{2}

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∑_{k=1}^{n} k = n(n+1)/2

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2φ² + 2φ + 5 = 0

9θ² + 7θ + 4 = 0

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e^{i\pi} + 1 = 0

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\lim_{n\to 0} \frac{\sin n}{n} = 1

∫₀^∞ e^(-t²) dt = √π / 2

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