Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:49Z

10y² + 2y + 6 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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e^{i\pi} + 1 = 0

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∫₀^∞ e^(-t²) dt = √π / 2

iħ ∂ψ/∂t = Ĥψ

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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e^{i\pi} + 1 = 0

8ψ² + 7ψ + 0 = 0

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∂y/∂γ = 8y

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{γ\to 0} \frac{\sin γ}{γ} = 1

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∑_{k=1}^{n} k = n(n+1)/2

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λ = h/p

d/dt [t^3] = 3t^2

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∑_{k=1}^{n} k = n(n+1)/2

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∇ × E = −∂B/∂t

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