Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 01:32Z
11φ² + 9φ + 3 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 9 8 ; 3 10 | = 66
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∫₀^∞ e^(-y²) dy = √π / 2
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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\lim_{y\to 0} \frac{\sin y}{y} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∑_{k=1}^{n} k = n(n+1)/2
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