Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:52Z

11n² + 5n + 4 = 0

iħ ∂ψ/∂t = Ĥψ

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∫₀^∞ e^(-x²) dx = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

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6ω² + 4ω + 4 = 0

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4φ² + 6φ + 2 = 0

11t² + 9t + 7 = 0

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det| 10 2 ; 3 11 | = 104

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∫₀^∞ e^(-φ²) dφ = √π / 2

12γ² + 9γ + 1 = 0

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PV = nRT

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∇²ω = 0

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8ψ² + 7ψ + 0 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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